@christianp@mathstodon.xyz Most of the time a(n)=a(n-1)+n, so can be "compressed" by looking into those n where it does not hold. What is interesting, quite many of those actually belong to A395531 itself!
n = 3, in A395531? yes, a(n)-a(n-1) = 4 = n + 1
n = 6, in A395531? - , a(n)-a(n-1) = 9 = n + 3
n = 11, in A395531? yes, a(n)-a(n-1) = 14 = n + 3
n = 16, in A395531? yes, a(n)-a(n-1) = 20 = n + 4
n = 22, in A395531? - , a(n)-a(n-1) = 30 = n + 8
n = 32, in A395531? yes, a(n)-a(n-1) = 38 = n + 6
n = 40, in A395531? yes, a(n)-a(n-1) = 47 = n + 7
n = 49, in A395531? yes, a(n)-a(n-1) = 57 = n + 8
n = 59, in A395531? yes, a(n)-a(n-1) = 68 = n + 9
n = 67, in A395531? - , a(n)-a(n-1) = 70 = n + 3
n = 70, in A395531? - , a(n)-a(n-1) = 80 = n + 10
n = 85, in A395531? yes, a(n)-a(n-1) = 96 = n + 11
n = 98, in A395531? yes, a(n)-a(n-1) = 110 = n + 12
https://gist.github.com/hellman/a4a56f013085edf379ac6377db0fa9bb